bash 在 shell 中解析 ps 和 grep 输出
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Parsing ps and grep output in shell
提问by Jeremy
I get the following message when I do a "ps -ef | grep port"
当我执行“ps -ef | grep port”时，我收到以下消息
apache 6215 1 0 11:20 ? 00:00:00 perl /scripts/myscript.pl -sn 4123E -sku HSME01-HW -port 8
Is there a way to parse the following:
有没有办法解析以下内容：
- start time (11:20)
- sn (4123E)
- sku (HSME01-HW)
- port (8)
- 开始时间（11:20）
- SN (4123E)
- sku (HSME01-HW)
- 端口 (8)
回答by Ansgar Wiechers
You can use awkfor both filtering and parsing:
您可以awk用于过滤和解析：
ps -ef | awk '/[p]ort/ {printf "start time: %s\nsn: %s\nsku: %s\nport: %s\n", , , , $NF}'
As glenn Hymanman pointed out in the comments the square brackets in the filter string prevent the expression from matching the filter string itself in the process list.
正如 glenn Hymanman 在评论中指出的，过滤字符串中的方括号会阻止表达式匹配进程列表中的过滤字符串本身。
回答by saeedgnu
Since the question is tagged as bash, using bash-only solutions (no awk or perl) is preferred...
由于问题被标记为bash，因此首选使用 bash-only 解决方案（无 awk 或 perl）...
LINE='apache 6215 1 0 11:20 ? 00:00:00 perl /scripts/myscript.pl -sn 4123E -sku HSME01-HW -port 8'
## Convert string to bash array
ARR=($LINE)
echo "start time (${ARR[4]})"
echo "sn (${ARR[10]})"
echo "sku (${ARR[12]})"
echo "port (${ARR[14]})"
## How to save the value?
START_TIME=${ARR[4]}
